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#1 (permalink) |
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Got the GMAT on my mind
Join Date: Jul 2009
Posts: 6
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Geometry polygon problem
This is pretty simple, but I'm not understanding the book's explanation. Help please.
Q. What is the measure of 2 of the 8 angles of a regular octagon? A. 270 degrees (135 degrees x 2) I guess I don't fully understand the properties of polygons. |
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#2 (permalink) |
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Within my grasp!
![]() ![]() Join Date: Aug 2009
Posts: 157
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Divide the recgular octagon into 8 triangles. Then the measure of the angle at the vertex is 45 (360/8). In each of the triangles, the sum of interior angles is 180, which leaves 135 as the sum of the remaining two angles of the triangles. Since its a regular octagon, Each angle is 135/2. This is just a half angle of the polygon. The other half angle (another 135/2) is from a neighboring triangle. This gives (135/2 + 135/2 = 135) as the value of each of the interior angles. So two interior angles would be 135x2 = 270. Hope this helps!!
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#5 (permalink) |
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I JUST got here.
Join Date: Aug 2009
Location: Bangalore
Posts: 21
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The formula for the total measure of the interior angles of any polygon is (n-2)*180, where n is the number of sides of the polygon. Using this formula we can find the total angle and divide by 8.
(8-2)*180=1080. when 1080/8=135/interior angle. so for 2 interior angles, it is 270 |
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#6 (permalink) | |
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This user's posts are moderated.
Join Date: Aug 2009
Posts: 29
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Quote:
Friend you can derive this formula: (n - 2)*PI = S; S = sum of internal angles of a nth degree polygon. So for a general octagon you can write S = 6*PI For a regular Octagon S = 8*theta; as all angle will be equal. So Sum of two angles = theta + theta = 2*theta = 6/4 * PI = 3/2*180 deg = 270 deg |
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