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#3 (permalink) | |
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TestMagic Guru-in-Training
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Posts: 726
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Quote:
-3+7=4>0 but x is not larger than y or x=7 y=3 7+3=10 x>y my vote for C (2) (x-y)(x+y)>0 x-y>0 and x>-y st 1 directly says that x>-y so x>y C ![]() |
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#5 (permalink) |
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TestMagic Guru
![]() ![]() ![]() ![]() Join Date: Jun 2008
Posts: 1,566
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1. X + Y > 0
X > -Y, INSUFFICIENT 2. X2 > Y2 X2 - Y2 > 0 (X+Y)(X-Y) > 0 Either X > -Y and X > Y or X < -Y and X < Y INSUFFICIENT Combining the two, (X+Y)(X-Y) > 0 from statement (1) (X-Y) > 0 (since (X+Y) > 0 from statement (1) ) X > Y SUFFICIENT Hence C. ![]() |
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#6 (permalink) | |
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TestMagic Guru-in-Training
![]() ![]() ![]() Join Date: May 2009
Posts: 726
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Quote:
first is x-y>0 and second (x+y)>0 the product of two positive numbers is always positive from the first we are given that x>-y or x+y>0 hence x-y>0 so x>y ![]() |
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