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#2 (permalink) |
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TestMagic Guru-in-Training
![]() ![]() ![]() Join Date: May 2009
Posts: 726
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(1/5)^m=(5^-1)^m=5^-m
(1/4)^18=(4^-1)^18=(2^-2)^18=2^-36 (10)^-35=(2*5)^-35=(2^-35)*(5^-35) (2^-36)/2^1=2^(-36-1)=2^-37 (i try to get rid off 2 from right part) (5^-m)*(2^-37)=(2^-35)*(5^-35) it is very stange but i can`t cancel exponent 2 totaly and i can`t find my mistake (5^-m)*(2^-2)=(5^-35) kuemura are you sure that you write all numbers correctly???? |
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#6 (permalink) | |
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Eager!
Join Date: Sep 2007
Posts: 47
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Quote:
5^-m x (2^2)^-18 = 2^-1 x(2 x5)^-35 5^-m x 2^(2x-18) = 2^-1 x 2^-35 x 5^-35 5^-m x2^-36 = 2^(-1 -35) x 5^-35 5^-m = 5^-35 -m = -35 m =35 hope this helps |
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