Difficult Permutations Problem - two tables lots of people...

[choked]

I'm having a lot of trouble making my answer look like the Official Answer. Can someone help?

Here's the problem:

In how many different ways can 12 people be seated at two tables with one seating 7 and the other seating 5?




Official Answer is 13,685,760, which, I think, comes from 12P5*4!*3!. Prime factorization of the Official Answer yields 2^10*3^5*5*11, which I figured must look something like (12*11*10*9*8*4*4*3*3).

Anybody want to help me out with this problem?

[choked]

Nevermind. I figured it out, no thanks to any of you.

12C5*6!*4!

thanks for nothing.