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#5 (permalink) |
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Within my grasp!
![]() ![]() Join Date: Nov 2004
Location: Delhi
Posts: 367
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Re: Hard one
any more thoughts on this one
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a month to first tame the beast, then lay it down; rip out its legs;then its horns;smash its skull;finally when it's totally helpless, gouge its eyes out and pull out a 750 plus - I'm BLOODTHIRSTY AS HELL |
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#6 (permalink) |
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I JUST got here.
Join Date: Jan 2005
Location: New Delhi
Posts: 21
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Re: Hard one
The method I followed was to reduce the Q to (x^6/ x ) * ( Y/Y)
the eqn An= (x ^ n -1)(1+ x + x^2 + x^3 +.... ) ----------------------------(1) and the eqn x(1+x(1+x(1+x...)))) which i call Z can be reduced to x( 1+x+x^2+x^3 ..) --------(2) from (1) and (2) we get An / Z = x^(n-1) / x therefore for getting answer x^5 (n-1) = 6 therefore n=7 answer: B |
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