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Thread: M-GMAT question

  1. #11
    Within my grasp! Stormgal 's dreams are becoming reality. Stormgal's Avatar
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    Re: M-GMAT question

    Quote Originally Posted by Vakul
    my approach:

    320 + 5x = 580 - .41x; x = # of days after price is same;

    solving for x; x is approximately 48, thus the requiremd price is 320 + 5 * 48 = 560 cents = $5.6

    took about 2 mins to solve
    Nice short cut! But how did you get the -.41x - ins't it -1.41?

  2. #12
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    Re: M-GMAT question

    Quote Originally Posted by Stormgal
    Nice short cut! But how did you get the -.41x - ins't it -1.41?

    it is decreasing at the rate of which is .41x

  3. #13
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    Re: M-GMAT question

    Hey,

    Looked strangely like upper 5th - lower 6th physics to me. You're given initial prices (velocities) and rates of increase/decrease (acceleration/deceleration).

    Time for prices to equate being the same,

    (P-320)/(5x) = (P-580)/(-0.4x), where P is the price when the commodities
    are equally expensive
    => 0.4P - 128 = 2900 - 5P

    => P = 3028/5.4, which approximates to 560 cents or $5.60


    Note: equation for motion under constant acceleration is, final velocity = initial velocity + rate of acceleration * time

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