sezuno Posted March 12, 2005 Share Posted March 12, 2005 Hi, I'm a new member and was hoping to get some help on the following question: If 15!/3^m is an integer, what is the greatest possible value of M? a. 4 b. 5 c. 6 d. 7 e. 8 I know the answer is c, but how? Thanks. Quote Link to comment Share on other sites More sharing options...
800needed Posted March 13, 2005 Share Posted March 13, 2005 Welcoem to TM! :) Anyway the perfet approach to this question is to write out 15! So 15!=15*14*13*12*11*10*9*8*7*6*5*4*3*2*1 So out of thoe what numbers are divisible by 3? well 15, 12, 9, 6, and 3. so 15=5*3, 12=3*4, 9=3*3, 6=3*2, and 3=3*1 Now count how many 3 you have there and you will see you have six 3s. so the answer can only be 6. Hope this help!:tup: Quote Link to comment Share on other sites More sharing options...
udaygrover Posted March 14, 2005 Share Posted March 14, 2005 Absolutely right...!! Now lets look at the question in a diferent way.... What if the question said 100!/2^m One cannot sit and find all numbers which are prsent and then add the nuber of 2's in it..right...so here is the trick first we need to find the number of multiples of 2 == 50 Then the number of multiples of 4 number of multiples of 8 number of multiples of 16 number of multiples of 32 number of multiples of 64 Therfore the answer for maximum value of m is == 50+25+12+6+3+1 = 97 if we do this for the current question 15!/3^m number of factors of 3 number of factors of 9 answer == 5 + 1 = 6 Hope u get the answer please pm me if u have ne more doubts on the same regards uday Quote Link to comment Share on other sites More sharing options...
Stormgal Posted March 14, 2005 Share Posted March 14, 2005 Absolutely right...!! Now lets look at the question in a diferent way.... What if the question said 100!/2^m One cannot sit and find all numbers which are prsent and then add the nuber of 2's in it..right...so here is the trick first we need to find the number of multiples of 2 == 50 Then the number of multiples of 4 number of multiples of 8 number of multiples of 16 number of multiples of 32 number of multiples of 64 Therfore the answer for maximum value of m is == 50+25+12+6+3+1 = 97 if we do this for the current question 15!/3^m number of factors of 3 number of factors of 9 answer == 5 + 1 = 6 Hope u get the answer please pm me if u have ne more doubts on the same regards uday Hi Uday - you are a genius - I was about to ask that question, that what if the number is large. Anyway, I hate to sound dumb, but why would one want to find the multiples of not only 2, but of 4, 8, 16, 32, etc? Quote Link to comment Share on other sites More sharing options...
Vakul Posted March 17, 2005 Share Posted March 17, 2005 Hi Uday - you are a genius - I was about to ask that question, that what if the number is large. Anyway, I hate to sound dumb, but why would one want to find the multiples of not only 2, but of 4, 8, 16, 32, etc? multiple of 2 will have only 1 factor of 2. multiple of 4 will have 2 factors of 2 multiple of 8 will have 3 factors of 2 multiple of 16 will have 4 factors of 2 Quote Link to comment Share on other sites More sharing options...
udaygrover Posted March 21, 2005 Share Posted March 21, 2005 Hi... Thats right... Hope you have understood the reason strom let me know if you still have a doubt uday Quote Link to comment Share on other sites More sharing options...
texaspunk Posted March 26, 2005 Share Posted March 26, 2005 Thanks all for excellent explanation. My only clarification is that the explanation states: find multiples of 2 and find multiples of 4 using the "less than symbol makes this explanation is a bit confusing. Because as we know the number of multiples of 2 must include 100 in order to get an answer of 25 and and the number of multiples of 4 in 100 must include the number 100 in order for the answer to be 25. (not or Am I missing something?:mad: Quote Link to comment Share on other sites More sharing options...
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