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Old 2005 April 18th, 08:03 PM   #1 (permalink)
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Strange Q

There is 200 gallons water in pool A and 500 gallons in pool B. From 12pm, water is poured into pool A at the rate of k gallons per minute and drawn out from pool B at the rate of m gallons per minute. In terms of k and m, in how many minutes, A and B would has same amount of water?
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Old 2005 April 18th, 09:16 PM   #2 (permalink)
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Re: Strange Q

LET T = TIME

200 + Tk = 500 - Tm
=> Tk + Tm = 300
=> T(k + m) = 300
=> T = 300/(k+m)
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Old 2005 April 27th, 08:51 PM   #3 (permalink)
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Re: Strange Q

Relative difference of water levels is 300
The relative velocity between the water in water in pool A and pool B is (K+M)
Time taken to level the both water levels is 300/(k+m)
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