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Old 2006 July 10th, 04:22 PM   #1 (permalink)
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finite set of numbers

Does S contain more negative numbers than positive numbers?

1. The product of all the numbers in S is -1,200
2. There are 6 numbers in S.
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Old 2006 July 11th, 07:15 PM   #2 (permalink)
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Question seems insufficient somehow, but based on the information you provided, I would answer no, because:

the product of all the numbers in S is a negative number => there are either 1, 3 or 5 negative numbers in the bunch. Obviously then S can contain either more negative numbers, or fewer, or equal numbers
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Old 2006 July 11th, 08:19 PM   #3 (permalink)
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I copied this question from gmat prep
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Old 2006 July 13th, 10:04 PM   #4 (permalink)
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I would say E
from 1:
Product of all number is negetive -> there are odd (1,3,5) number of negetive number(s). So there could be 1 ngetive and 5 positive number
or there could be 5 negetive and 1 positive number; both series would have same result (a negetive value)

From 2
There are 6 numbers does not add much to it.

So, E
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Old 2006 July 13th, 10:10 PM   #5 (permalink)
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Agreed E.

Obviously A,B and D are not right.
Now let's try and see if it is C or E.

Examples of 6 number set satisfying both conditions that make it go either way:

{1200, -1, 1, 1 ,1 ,1} more pos.
{1200, -1, -1, -1 -,1 ,-1} more neg.

So E.
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Old 2006 July 23rd, 10:46 AM   #6 (permalink)
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Vote for E
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