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Old 2006 August 5th, 09:46 AM   #1 (permalink)
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Question Please help solve this question from Gmatprep

How to solve this question(short cut)..I have no clue.

Problem solving

For every positive even integer n, the function H(n) is defined to be the product of all the even integers from 2 to n, inclusive. If P is the smallest prime factor of H(100)+1 then P is ?

a) between 2 and 10
b) between 10 and 20
c) between 20 and 30
d) between 30 and 40
e) greater than 40

answer (highlight): E
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Old 2006 August 5th, 09:58 AM   #2 (permalink)
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h(n)=2*4*6*8*----*n
h(100)=2*4*6*8*----*100
=2^50 (1*2*3*------*50)
so, h(100) will be divisible by all the prime numbers b/w 2 & 50, h(100)+1 will not be divisible by any of the prime numbers b/w 2 & 50 since it will leave remainder 1 after dividing h(100)+1 by any of the prime number b/w 2&50.
so, the next prime number by which it could be divisible should be greater than 50, the smallest prime factor of h(100)+1 should be greater than 40 i.e. answer (E)

Or por favor, El Seņor refer to
http://www.urch.com/forums/gmat-prob...ction-h-n.html (Function h(n))

Last edited by manish8109 : 2006 August 5th at 09:58 AM. Reason: Automerged post
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Old 2006 August 5th, 01:59 PM   #3 (permalink)
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Thanks a million, manish. Very appreciate your help.
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