deeppurple Posted August 18, 2006 Share Posted August 18, 2006 a) Each of the 32 schools has 2 classes. The number of the teachers is 37.One class (at least?) has one teacher; one teacher teaches at least one class and at most 3 classes. What are the greatest number and the least number of the teachers who teach 3 classes? b) When two numbers are taken out from 1, 3, 5, 7, 9, 11, 13, 15, 17, 19, what is the deviation of the numbers left. 1) The median of the left numbers is 10 2) The average does not change c) A table, the first line gives the number of workers (some of the numbers is expressed by x); the second line gives the corresponding working hours. What is the total number of the workers? 1) The average working hours is ...(some value given) 2) The workers work less than or equal to 1 hour is exactly half the total workers NE 1? these are questions from the JJ's..:-) Quote Link to comment Share on other sites More sharing options...
sangarelli Posted August 19, 2006 Share Posted August 19, 2006 The maximum number would be 37 coz all of them can teach three classes.And the least number is zero coz nonw of them require to teach more than two classes. Question 2 would be (E) Quote Link to comment Share on other sites More sharing options...
shivalib Posted August 19, 2006 Share Posted August 19, 2006 hi.. could you pls provide options to q1 is the answer e for q2 or c(not too sure) q3 is not clear..could you elaborate? Quote Link to comment Share on other sites More sharing options...
shivalib Posted August 23, 2006 Share Posted August 23, 2006 ans pls as its been long now...i found these questions interesting...:) Quote Link to comment Share on other sites More sharing options...
pharmindo Posted August 23, 2006 Share Posted August 23, 2006 I think answer for Q1 is 1 and 9. There are 64 classes in total (32 x 2),and 37 teachers which each of them teach at least 1 class. ==> 64 - 37 = 27 2x + 3y = 27 x= 0 --> y = 9 x= 12 --> y = 1 Q2: E Quote Link to comment Share on other sites More sharing options...
mrajatish Posted October 2, 2006 Share Posted October 2, 2006 it should be x + 2y = 27, since each teacher will teach either one or more class (they already teach one class). Hence, max (y) = 13 and min (y) = 0. Quote Link to comment Share on other sites More sharing options...
rajkishor Posted October 2, 2006 Share Posted October 2, 2006 x1 = no of teachers who teach 1 class x2 = no of teachers who teach 2 class x3 = no of teachers who teach 3 class x1 + x2 + x3 = 37 x1 + 2x2 + 3x3 = 64 From above two equations, we have, x2 + 2x3 = 27 We can conclude that, Minimum x3 = 0 and Maximum x3 = 13 Quote Link to comment Share on other sites More sharing options...
GREMAT Posted October 3, 2006 Share Posted October 3, 2006 a) Each of the 32 schools has 2 classes. The number of the teachers is 37.One class (at least?) has one teacher; one teacher teaches at least one class and at most 3 classes. What are the greatest number and the least number of the teachers who teach 3 classes? b) When two numbers are taken out from 1, 3, 5, 7, 9, 11, 13, 15, 17, 19, what is the deviation of the numbers left. 1) The median of the left numbers is 10 2) The average does not change c) A table, the first line gives the number of workers (some of the numbers is expressed by x); the second line gives the corresponding working hours. What is the total number of the workers? 1) The average working hours is ...(some value given) 2) The workers work less than or equal to 1 hour is exactly half the total workers NE 1? these are questions from the JJ's..:-) Total classes: 64 Total teachers: 37 The least number: 1 37 teachers * 1 class = 37 classes of those 37, 24 teaches 1 additional class = 24 at least one teacher has to teach 3 classes (37+24+3=64) The greatest number: 13 x=number of teachers who teach 1 class y=number of teachers who teach 3 classes x+y=37 x+3y=64 solving this set of equations for x, we get x=23,5 and 3y=40,5 Hence, the greatest integer for y is 13. Q2 the median and the mean is 10 we can take 1 and 19, or 9 and 11 and the medain and the mean reamain the same. Therefore, we can`tell the deviation Ans E I need more info to solve question 3. Quote Link to comment Share on other sites More sharing options...
A tool Posted October 5, 2006 Share Posted October 5, 2006 Q1. 13 and 0 Q2. E Q3. Q not clear Quote Link to comment Share on other sites More sharing options...
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