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Reply With QuoteTotal length = Circumference = 2*pi*r = 8pi
Length of arc RTU = 4pi/3 => if O is the center, angle ROU = 4pi/3/(8pi) * 360 = 60 degrees
=> OR = OU = 4
ORU is an equivilateral triangle
RU will also be 4 as all 3 angles are 60 degrees
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The points R, T, and U lie on a circle that has radius 4. If the length of arc RTU is (4pi)/3, what is the length of line segment RU?
Last edited by gurdip79; 10-15-2006 at 06:11 PM.
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Total length = Circumference = 2*pi*r = 8pi
Length of arc RTU = 4pi/3 => if O is the center, angle ROU = 4pi/3/(8pi) * 360 = 60 degrees
=> OR = OU = 4
ORU is an equivilateral triangle
RU will also be 4 as all 3 angles are 60 degrees
Last edited by GMAT-HELP; 10-16-2006 at 02:52 AM.
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