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Thread: Standard Deviation Problems

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    Standard Deviation Problems

    • There are these 8 numbers in a set 9.4,9.9,9.9,9.9,10.0,10.2,10.2,10.5 The mean and standard deviation of the 8 numbers are 10.0 and 0.3 respectively, what percent of the 8 numbers are within 1 standard deviation of the mean?
      a) 90%
      b) 85%
      c) 80%
      d) 75%

      e) 70%
    Need a detailed solution: Thanks

  2. #2
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    1 standard deviation in this case is 9.7 to 10.3 six numbers are within this range so the answer is 6/8 * 100 = 75%

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    Agree; three 9.9's ,10.0 & two 10.2's are within 1 SD of the mean (10.0) => 6/8 * 100 = 75%

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    Can anyone please explain the solution above in detail. What does 1 standard deviation mean ?

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    The question says "The mean and standard deviation of the 8 numbers are 10.0 and 0.3 respectively" so:

    mean = 10
    sd = 0.3

    "one standard deviation" = 1*(sd) = 0.3.

    two standard deviations would be 2*(sd) = 0.6, etc.

    A number that is within SD away from the mean could be greater or less than the mean -- in this case, it could be either of the following:

    greater than 10 - 0.3 = 9.7
    less than 10 + 0.3 = 10.3

    ---
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    help me with this standard deviation question

    The fourth grade at school X is made up of 300 students who have a total weight of 21,600 pounds.
    If the weight of these four graders has a normal distribution and standard deviation equals 12 pounds, approximately what percentage of the fourth graders weighs more than 84 pounds?

    a 12%
    b 16%
    c 36%
    d 48%
    e 60%

    need detailed explanation,,and also want to know what are bell curve questions and how it will relate with standard deviaion. thanks

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    here μ = 72
    μ + 1.σ = 72 + 12 = 84

    Standard Deviation Problems-350px-standard_de-.png

    % of students above 84 = 13.6% + 2.1% + 0.1% = 14.8% ≈ 15%

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    Where did you get this question? My believe is that GMAT will not be asking questions like this....

    Mean = 21600/300 = 72

    Mean + 1sigma (std dev) = 72 + 12 = 84

    +/- 1<sigma> covers 68.2% (34.1% + 34.1%) of the normal distribution. Therefore, remain distribution of data 100% - 68.2% = 31.8%.

    Since we care only about data points above 84 lbs => 31.8 / 2 = 15.9% = 16%

    What's the answer?

    +Matt

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    This question is not from GMAT preparation. This is from cracking the GRE from princeton review. Since i got stuck by this question that why asked it, and yes the correct answer is 16%

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    PERMUTATION AND COMBINATION

    A teacher prepares a test. She gives 5 objective type question out of which 4 have to be answered. Find the total ways in which they can be answered if the first 2 questions have 3 choice and last 3 have 4 choice.

    help me with this question,,is there any specific formula applied in thes type of questions???

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