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#11 (permalink) |
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Within my grasp!
![]() ![]() Join Date: Jul 2007
Posts: 125
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Am I missing out something??
Statement 1: k = n* 2^6 (where n is some integer) n can be either odd or even ... in either case it's insufficient (e.g if n=6 then K can not be 2^r for some positive integer r whereas if n=2,4,8 etc then it's possible) Statement 2: K is not divisible by any odd integer>1 IMO this is also insufficient (e.g again K is divisible by 6 ... now it can not be 2^r for some positive integer r) when we combine 1 & 2 still it's not sufficient (assume K= 6*2^6 .... both conditions satisfied but still k !=2^r where r is a integer on other hand if we have k = 4*2^6 it's possible ...) So it turns ou to be E ... Correct me pls ...!! |
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#12 (permalink) |
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Magoosh, Co-Founder
![]() ![]() Join Date: Jun 2009
Posts: 134
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@Sommukh
In Statement 2, K cannot be divisible by 6 because that would mean K is also divisible by 3. The statement says that K is not divisible by any odd integer > 1. The trick here is understanding prime factorization of a number. A number, K, is divisible by all numbers in its prime factorization. But 2 can be the only even number in a prime factorization (because 2 is the only non-odd prime number). Because the statement says that K is not divisible by any odd numbers greater than 1, the prime factorization of K must be 2^r. Hope that helps!
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