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Old 2009 August 11th, 06:33 PM   #11 (permalink)
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Am I missing out something??

Statement 1: k = n* 2^6 (where n is some integer)
n can be either odd or even ... in either case it's insufficient (e.g if n=6 then K can not be 2^r for some positive integer r whereas if n=2,4,8 etc then it's possible)

Statement 2: K is not divisible by any odd integer>1
IMO this is also insufficient (e.g again K is divisible by 6 ... now it can not be 2^r for some positive integer r)

when we combine 1 & 2 still it's not sufficient (assume K= 6*2^6 .... both conditions satisfied but still k !=2^r where r is a integer on other hand if we have k = 4*2^6 it's possible ...) So it turns ou to be E ... Correct me pls ...!!
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Old 2009 August 11th, 09:40 PM   #12 (permalink)
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@Sommukh
In Statement 2, K cannot be divisible by 6 because that would mean K is also divisible by 3. The statement says that K is not divisible by any odd integer > 1.

The trick here is understanding prime factorization of a number. A number, K, is divisible by all numbers in its prime factorization. But 2 can be the only even number in a prime factorization (because 2 is the only non-odd prime number). Because the statement says that K is not divisible by any odd numbers greater than 1, the prime factorization of K must be 2^r.

Hope that helps!
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Old 2009 August 13th, 08:34 AM   #13 (permalink)
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thank you !! ... that was silly on my part ...
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