If K is an integer greater than 1, is k equal to 2^r for some positive integer r.
(1)k is divisible by 2^6
(2)k is not divisible by any odd integer greater than 1.
If K is an integer greater than 1, is k equal to 2^r for some positive integer r.
(1)k is divisible by 2^6
(2)k is not divisible by any odd integer greater than 1.
My approach --->
Statement 1: k = n* 2^6 (where n is some integer)
Sufficient.
Post edit: It is insufficient.
Statement 2: 2 is the only prime factor of k.
Sufficient.
Answer : Either of the statements are sufficient. (D)
Post edit: IMO its B. Made a silly error earlier.
OA please!
Last edited by coyote; 11-08-2007 at 04:56 AM.
IMO B
A being divisible by 2^6 does not imply that it has no other odd factors. it could be 3*2^6 satisfy 1 but cannot be expressed as a power or 2
2. K is greater than and not divisible by any odd number implies it has to be a power of 2
Thanks OA is B
Answer : B
is k = 2^r
1.] k = 2^6 * p [ p can be odd or even ..] - insuff to answer
2.] k = 2^ some positive integer q [ suff to answer ]
So B is the choice.
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