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Thread: GMAT Prep Question

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    Eager! sharad22 just joined TestMagic.
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    GMAT Prep Question

    If K is an integer greater than 1, is k equal to 2^r for some positive integer r.
    (1)k is divisible by 2^6
    (2)k is not divisible by any odd integer greater than 1.

  2. #2
    TestMagic Fan! coyote radiates success. coyote's Avatar
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    My approach --->

    Statement 1: k = n* 2^6 (where n is some integer)
    Sufficient.

    Post edit: It is insufficient.

    Statement 2: 2 is the only prime factor of k.
    Sufficient.

    Answer : Either of the statements are sufficient. (D)
    Post edit: IMO its B. Made a silly error earlier.

    OA please!
    Last edited by coyote; 11-08-2007 at 04:56 AM.

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    Within my grasp! pandeyrav is on the way! pandeyrav's Avatar
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    IMO B

    A being divisible by 2^6 does not imply that it has no other odd factors. it could be 3*2^6 satisfy 1 but cannot be expressed as a power or 2

    2. K is greater than and not divisible by any odd number implies it has to be a power of 2

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    TestMagic Guru-in-Training prreeet just joined TestMagic. prreeet's Avatar
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    Quote Originally Posted by pandeyrav View Post
    IMO B

    A being divisible by 2^6 does not imply that it has no other odd factors. it could be 3*2^6 satisfy 1 but cannot be expressed as a power or 2

    2. K is greater than and not divisible by any odd number implies it has to be a power of 2
    What if k is prime?

    IMO C
    Stmt. 1 tells us that k = m * 2^6
    Stmt. 2 tells us that k is not divisible by odd>1,

    combining, m can be 1 or 2^z
    hence C

  5. #5
    Within my grasp! pandeyrav is on the way! pandeyrav's Avatar
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    Quote Originally Posted by prreeet View Post
    What if k is prime?

    IMO C
    Stmt. 1 tells us that k = m * 2^6
    Stmt. 2 tells us that k is not divisible by odd>1,

    combining, m can be 1 or 2^z
    hence C
    it cannot be a prime as it says no odd number greater than 1 divides it. All primes are divisible by one and themselves.

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    TestMagic Guru-in-Training prreeet just joined TestMagic. prreeet's Avatar
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    Quote Originally Posted by pandeyrav View Post
    it cannot be a prime as it says no odd number greater than 1 divides it. All primes are divisible by one and themselves.
    makes sense...
    so it should be B
    wats the OA?

  7. #7
    TestMagic Fan! coyote radiates success. coyote's Avatar
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    Quote Originally Posted by pandeyrav View Post
    IMO B

    A being divisible by 2^6 does not imply that it has no other odd factors. it could be 3*2^6 satisfy 1 but cannot be expressed as a power or 2

    2. K is greater than and not divisible by any odd number implies it has to be a power of 2
    Oops! You are right. A silly mistake on my part! Thanks pandey!

    IMO its B.

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    Eager! sharad22 just joined TestMagic.
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    Thanks OA is B

  9. #9
    Within my grasp! wizind77 just joined TestMagic. wizind77's Avatar
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    Answer : B

    is k = 2^r

    1.] k = 2^6 * p [ p can be odd or even ..] - insuff to answer
    2.] k = 2^ some positive integer q [ suff to answer ]

    So B is the choice.

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