Go Back   TestMagic Forums > Test preparation > GMAT > GMAT Math
Register Forum Rules FAQ Members List Calendar Search Today's Posts Mark Forums Read

Reply
 
LinkBack Thread Tools Search this Thread Display Modes
Old 2007 November 7th, 04:46 PM   #1 (permalink)
Eager!
 
Join Date: Aug 2007
Posts: 80
sharad22 just joined TestMagic.
GMAT Prep Question

If K is an integer greater than 1, is k equal to 2^r for some positive integer r.
(1)k is divisible by 2^6
(2)k is not divisible by any odd integer greater than 1.
sharad22 is offline  
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!Google Bookmark this Post!Reddit!
Reply With Quote
Old 2007 November 7th, 04:51 PM   #2 (permalink)
TestMagic Fan!
 
coyote's Avatar
 
Join Date: Aug 2007
Location: India
Posts: 347
coyote radiates success.
My approach --->

Statement 1: k = n* 2^6 (where n is some integer)
Sufficient.

Post edit: It is insufficient.

Statement 2: 2 is the only prime factor of k.
Sufficient.

Answer : Either of the statements are sufficient. (D)
Post edit: IMO its B. Made a silly error earlier.

OA please!

Last edited by coyote : 2007 November 8th at 04:56 AM.
coyote is offline  
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!Google Bookmark this Post!Reddit!
Reply With Quote
Old 2007 November 7th, 06:10 PM   #3 (permalink)
Within my grasp!
 
pandeyrav's Avatar
 
Join Date: Mar 2006
Location: Atlanta
Posts: 284
pandeyrav is on the way!
IMO B

A being divisible by 2^6 does not imply that it has no other odd factors. it could be 3*2^6 satisfy 1 but cannot be expressed as a power or 2

2. K is greater than and not divisible by any odd number implies it has to be a power of 2
pandeyrav is offline  
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!Google Bookmark this Post!Reddit!
Reply With Quote
Old 2007 November 8th, 01:33 AM   #4 (permalink)
TestMagic Guru-in-Training
 
prreeet's Avatar
 
Join Date: Oct 2007
Posts: 578
prreeet just joined TestMagic.
Quote:
Originally Posted by pandeyrav View Post
IMO B

A being divisible by 2^6 does not imply that it has no other odd factors. it could be 3*2^6 satisfy 1 but cannot be expressed as a power or 2

2. K is greater than and not divisible by any odd number implies it has to be a power of 2
What if k is prime?

IMO C
Stmt. 1 tells us that k = m * 2^6
Stmt. 2 tells us that k is not divisible by odd>1,

combining, m can be 1 or 2^z
hence C
prreeet is offline  
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!Google Bookmark this Post!Reddit!
Reply With Quote
Old 2007 November 8th, 02:17 AM   #5 (permalink)
Within my grasp!
 
pandeyrav's Avatar
 
Join Date: Mar 2006
Location: Atlanta
Posts: 284
pandeyrav is on the way!
Quote:
Originally Posted by prreeet View Post
What if k is prime?

IMO C
Stmt. 1 tells us that k = m * 2^6
Stmt. 2 tells us that k is not divisible by odd>1,

combining, m can be 1 or 2^z
hence C
it cannot be a prime as it says no odd number greater than 1 divides it. All primes are divisible by one and themselves.
pandeyrav is offline  
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!Google Bookmark this Post!Reddit!
Reply With Quote
Old 2007 November 8th, 03:25 AM   #6 (permalink)
TestMagic Guru-in-Training
 
prreeet's Avatar
 
Join Date: Oct 2007
Posts: 578
prreeet just joined TestMagic.
Quote:
Originally Posted by pandeyrav View Post
it cannot be a prime as it says no odd number greater than 1 divides it. All primes are divisible by one and themselves.
makes sense...
so it should be B
wats the OA?
prreeet is offline  
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!Google Bookmark this Post!Reddit!
Reply With Quote
Old 2007 November 8th, 04:55 AM   #7 (permalink)
TestMagic Fan!
 
coyote's Avatar
 
Join Date: Aug 2007
Location: India
Posts: 347
coyote radiates success.
Quote:
Originally Posted by pandeyrav View Post
IMO B

A being divisible by 2^6 does not imply that it has no other odd factors. it could be 3*2^6 satisfy 1 but cannot be expressed as a power or 2

2. K is greater than and not divisible by any odd number implies it has to be a power of 2
Oops! You are right. A silly mistake on my part! Thanks pandey!

IMO its B.
coyote is offline  
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!Google Bookmark this Post!Reddit!
Reply With Quote
Old 2007 November 8th, 01:46 PM   #8 (permalink)
Eager!
 
Join Date: Aug 2007
Posts: 80
sharad22 just joined TestMagic.
Thanks OA is B
sharad22 is offline  
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!Google Bookmark this Post!Reddit!
Reply With Quote
Old 2007 November 9th, 06:03 PM   #9 (permalink)
Within my grasp!
 
wizind77's Avatar
 
Join Date: Oct 2007
Posts: 138
wizind77 just joined TestMagic.
Answer : B

is k = 2^r

1.] k = 2^6 * p [ p can be odd or even ..] - insuff to answer
2.] k = 2^ some positive integer q [ suff to answer ]

So B is the choice.
wizind77 is offline  
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!Google Bookmark this Post!Reddit!
Reply With Quote
Old 2009 August 8th, 10:13 AM   #10 (permalink)
TestMagic Guru-in-Training
 
Join Date: Feb 2005
Posts: 771
sgmat just joined TestMagic.
please explain in more details i m not able to understand this one

thanks!
sgmat is offline  
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!Google Bookmark this Post!Reddit!
Reply With Quote
Reply


Thread Tools Search this Thread
Search this Thread:

Advanced Search
Display Modes

What you can do
You cannot post new threads
You cannot post replies
You cannot post attachments
You cannot edit your posts

vB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are On
Pingbacks are On
Refbacks are On


All times are GMT. The time now is 08:53 AM.

Contact TestMagic   TestMagic Forums      Archive   Privacy Statement

TestMagic Locations   Legal   Privacy


SEO by vBSEO 3.2.0
Copyright © 2009 TestMagic
Ad Management by RedTyger

Scroll Up