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#1 (permalink) |
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Trying to make mom and pop proud
Join Date: Jun 2008
Posts: 2
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A couple of tricky GMAT math questions
Hi all:
Here are a couple of questions, which I found tricky and could not get to the correct answer. I look forward to inputs from you guys: 1. If n and y are positive integers and 450y = n^3, which of the following must be an integer: a. y/(3x5x(2^2)) b. y/((3^2)x5x2) c. y/(3x2x(5^2)) 2. If x^4 + y^4 = 100, then the greatest possible value of x is between A. 0 and 3 B. 3 and 6 C. 6 and 9 D. 9 and 12 E. 12 and 15 I shall post the answers soon. Thanks for everyone's time and I look forward to your response. Cheers, chalven. |
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#3 (permalink) |
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Trying to be focused
![]() ![]() Join Date: May 2008
Location: CA
Posts: 106
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1) is A
450=3^2*5^2*2 Hence Y need to be multiple of 3*5*2^2 to make an integer cubed. 2) is B Nothin is said about x, y being non zero or integers. So the y can be 0 for x to be maxiumum therefore 100^.25=3.xx |
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#6 (permalink) | |
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Eager!
![]() Join Date: Jul 2008
Posts: 30
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Quote:
My weakness in quan is always on properties of numbers. It's worse with DS. Examples are those questions like "xyz is a three digit number, is xyz>550" Any good advice to improve on this ? |
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#7 (permalink) |
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Confucius is thinking !!
![]() ![]() Join Date: Jul 2008
Location: US
Posts: 109
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Same here I am struggling with number properties. Remember in GMAT most of these things come as part of DS..so I consider myself in deep trouble. I hardly get such questons correct. Any clues guys how we can correct that?
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#8 (permalink) |
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Eager!
![]() Join Date: Jul 2008
Posts: 30
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Right now, just keep practising and read the OG explaination. I'm ok with those questions that have proper systemetic methods to derive the answer, with proper equations etc. But I'm having problem with those which require trial and error. Test with number 2, 3, 5, 7... Sometimes will miss out certain answers or possibilities
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#10 (permalink) |
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Trying to make mom and pop proud
![]() Join Date: Jun 2008
Posts: 26
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Gags - Each prime factor of a cubed integer must also be cubed. So if a, b, and c are the prime factors of n, a^3, b^3, and c^3 must be factors of n^3.
We see that n^3 is equal to 450*y. Doing the prime factorization of 450 gives us 2*3*3*5*5. So we have 2, 3^2, and 5^2. Because 450*y is equal to a cube, y needs to complete the cube by filling in the missing factors. So y must include 2^2, 3, and 5. Now look at the answer choices. A has exactly those factors in the denominator, which means that they must completely cancel out and leave only the numerator, i.e. an integer. B has an extra 3 in the denominator, and C has an extra 5 in the denominator. We cannot be sure that these will cancel out, so we cannot be sure that B or C will be an integer. I hope that helped. ![]() |
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