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#11 (permalink) | |
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Eager!
![]() Join Date: Aug 2008
Posts: 82
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now we now consider the cases for x < 0 and x >0 I when x > 0 then y = 2x and 2x > 0 as we know now that y can only by 0 or any negative integer then this possibility is ruled out. |
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#12 (permalink) |
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Within my grasp!
![]() ![]() Join Date: Jun 2008
Posts: 103
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What is the median number of employees assigned per project for the projects at Company Z?
(1) 25 percent of the projects at Company Z have 4 or more employees assigned to each project. (2) 35 percent of the projects at Company Z have 2 or fewer employees assigned to each project For this question all of us are assuming the median is got to be an integer. Is this assumption correct? Why can't a median be a decimal number.. |
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#13 (permalink) |
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Eager!
![]() Join Date: Sep 2008
Posts: 79
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Sunny...
I don't think that employees in option 2 can be inclusive o fproj in option one.. as option 1 states clearly that no of Emp . >= 4 second option clearly states no. of emp <= 2 hence those clearly are mutually exclusive remaining emp....between 2 and 4 hence, 3 seems to be right answer. |
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#18 (permalink) |
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Within my grasp!
![]() ![]() Join Date: Jun 2008
Posts: 332
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#19 (permalink) | |
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Within my grasp!
![]() ![]() Join Date: Jun 2008
Posts: 332
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am not able to get you correctly.Can you explain with example what you mean to say ![]() |
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#20 (permalink) | |
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Within my grasp!
![]() ![]() Join Date: Jun 2008
Posts: 332
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![]() Well.....lets see the OA on this..... Based on it we can assume if we can assume or not ![]() |
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