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Old 2008 October 5th, 12:59 PM   #1 (permalink)
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Tennis balls ??

Cylindrical tennis-ball cans are being packed into cartons. If each can has a radius of 2 inches and a height of 12 inches, and the dimensions of each carton are 14 inches by 16 inches by 20 inches, what is the maximum number of tennis-ball cans that can fit in each carton?

12
15
20
24
40
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Old 2008 October 5th, 01:21 PM   #2 (permalink)
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20.

We need to fit the maximum number of cans and hence we need to make sure that the empty space in the carton should be min.

As the height is 12; choose the side 14 as the height so that only 2 inches are wasted above the placed cans. If we choose 16 or 20 then more than 2 inches are wasted.

Now we need to fit 4 inch diameter circles in a rectangular box of 16*20.

We can fit 4 rows (with 5 cans in a row).
Hence 20.
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Old 2008 October 5th, 01:28 PM   #3 (permalink)
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Since the dimensions are all greater than the height of can(12) we should take the base area as 16*20 so that we get the max area out. 4*5 cans can fit in area of 16*20
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Old 2008 October 5th, 07:31 PM   #4 (permalink)
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nice one, shooter..
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Old 2008 October 5th, 09:28 PM   #5 (permalink)
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Yeah good one shooter and pgmgmat76
I got 25.5 as i was equating the areas pi*r^2 = 16*20 but i got my mistake now.
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Old 2008 October 6th, 06:47 PM   #6 (permalink)
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This is what I think,

Take 20 as the height. As the tennis cans are 12 inches in height, first arrange the tennis cans, standing, over an area of 14*16. U get 14 cans in.
Now we have 8 inches left out in the height part. Get the tennis cans in horizontally. Got the point???

Which means, we have a volume of 8*14*16 and we have a tennis can of 4*4*12. That is 9 cans.

That makes the total 23...

Pls. correct me if I am wrong.
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Old 2008 October 6th, 06:50 PM   #7 (permalink)
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Oops! I got my mistake!!

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