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#2 (permalink) |
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Within my grasp!
![]() ![]() Join Date: Sep 2008
Posts: 138
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Good Q
IMO E Here is how. 324700 to 458600 Let us consider intervals now 1. 324a13 what are the values a can take. 7, 8, 9 so 3C1 2. 32ab13 a can take values 5, 6, 7, 8, 9 ( 4 is already considered in 1) 5C1 b can take values from 0 to 9 so 10C1....5c1X10C1 3. 3abc13.. a takes values 3 to 9 so 7C1 b and c takes values 0 to 9 so... 7C1X10C1X10C1 now we need to do the same thing with 458600 and I get E Hope I made sense |
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#4 (permalink) |
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Within my grasp!
![]() ![]() Join Date: Jul 2008
Location: hydearbad
Posts: 107
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The questions says we need to find no of XXXXX13 between 324700 to 458600
for every hundred we can only have one 13 so if we calculate no of hundreds between 324700 to 458600 we get the solution I.e is 458600-324700=133900 divding by 100 we 1339 answer-E |
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