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## Trip Problem

During a trip, Francine traveled x percent of the total distance at an average speed of 40 miles per hour and the rest of the distance at an average speed of 60 miles per hour. In terms of x , what was Francine's average speed for the entire trip?

A. (180-x)/2

B. (x+60)/4

C. (300-x)/5

D. 600/(115-x)

E. 12000/(x+200)

Official Guide
SPOILER: E

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Let t be total distance

distance at 40mph = tx/100
time at 40mph = tx/(100*40)

distance at 60mph = t(100-x)/100
time at 60mph = t(100-x)/(100*60)

Total distance/Total time = t/[tx/4000 + t(100-x)/6000]
=12000/(x+200)

gives E.

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Originally Posted by e.cartman
Let t be total distance
time at 40mph = tx/(100*40)
time at 60mph = t(100-x)/(100*60)
Total distance/Total time gives E.
Can you explain step by step?

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5. Good post? |
Let p be the total distance,
Let t1 be the time he takes to travel x percent of p then t1=p(x/100))/40=p*x/4000
Let t2 be the time he takes to travel the rest of p then t2=p (1-x/100)/60=p*(100-x)/6000
Average= total distance/ total time= p/(t1+t2)= p/[px/4000+p(100-x)/6000] =12000/3x+2(100-x)= 12000/(200+x)

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Avg speed = Total distance/Total time taken

Let the total distance be D KM
then distance @ 40 miles/hr = D*x/100 and the time taken D*x/4000

distance @ 60 miles/hr = D*(100-x)/100 & the time taken D*(100-x)/6000

Avg. Speed = D/(D*x/4000 + D*(100-x)/6000) => 12000/(x+200)

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Originally Posted by cartera
Can you explain step by step?

Distance Traveled (D) = Average Speed (S) * Time (T)

D = S * T

S = D / T

Time for which she traveled at 40 miles per hour
T1 = ((x/100)* D)/ 40 = xD/4000

Time for which she traveled at 60 miles per hour
T2 = (100-x)D/6000

Now Average speed of the journey = Total Distance/ (T1 + T2)

Total Distance is D

Substituting the values you will get the answer . Hope that helps

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