


Both couples sit together=2*2*!3=24
Assume A is couple 1 (together), B1 and B2 are couple 2 and C is single person
AB1CB2
AB2CB1
B1AB2C
B1ACB2
B2AB1C
B2ACB1
B1CAB2
CB1AB2
B2CAB1
CB2AB1
B2CB1A
B1CB2A
Only 1st couple sits together=2*12=24 (multiplying by 2 as couple A can also be arranged in 2 ways)
Only 2nd couple sits together=2*12=24 (same as above)
Total = 24+24+24=72
Total ways in which 5 persons can be seated = !5=120
Prob = 1-72/120=48/120=2/5
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