Is there a formula

[grad.mad]

for calculating the max. no.of triangles that can be drawn in a polygon ?

 

Somewhere in this forum i remember reading a hexagon can contain a max. of 6 triangles.

[Lock]

grad.mad:

The maximum number of triangles in a regular hexagon is 20. Out ouf these 20, 6 are isosceles and 2 are equilateral. Here's the formula for an 'n' sided regular polygon and the maximum possible number of triangles drawn by using all of the vertices of this polygon:

n!/3!(n-3)!

For a regular hexagon we have: [6!/3!(6-3)!]=20.

[dungtruong]

grad.mad:

The maximum number of triangles in a regular hexagon is 20. Out ouf these 20, 6 are isosceles and 2 are equilateral. Here's the formula for an 'n' sided regular polygon and the maximum possible number of triangles drawn by using all of the vertices of this polygon:

n!/3!(n-3)!

For a regular hexagon we have: [6!/3!(6-3)!]=20.

 

 

Agree with you: the same formula is 3C6.