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Old 2009 October 16th, 08:46 AM   #11 (permalink)
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What's the OA?
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Old 2009 October 16th, 08:47 AM   #12 (permalink)
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Quote:
Originally Posted by touche View Post
You are absolutely right!
No calculations needed in this case, where ever point P(X,Y) is, Q will be (y,x)!
I don't understand? Can someone explain to me, pls...
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Old 2009 October 16th, 11:55 AM   #13 (permalink)
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OA is A.
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Old 2009 October 16th, 02:54 PM   #14 (permalink)
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Quote:
Originally Posted by Infinite7 View Post
I don't understand? Can someone explain to me, pls...
Infinite7, let me try.....though im not a maths student...
If P is -2,0 then Q is 2,0... likewise
if P is 0,2 then Q is 2,0

If two triangles were to be made by drawing P and Q to x axis....you will have a fixed hyp.

As the hypotenuse is constant the squares of the adjacent and opposite sides will always be equal.

or a1^2+b2^2=a2^2+b2^2
I guess one could prove it from here on....

a1^2-a2^2=b2^2-b1^2
(a1+a2)(a1-a2)=(b2+b1)(b2-b1).. lost here!
try taking values.... you will get what im trying to suggest!
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Old 2009 October 17th, 07:36 PM   #15 (permalink)
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Quote:
Originally Posted by touche View Post
Infinite7, let me try.....though im not a maths student...
If P is -2,0 then Q is 2,0... likewise
if P is 0,2 then Q is 2,0

If two triangles were to be made by drawing P and Q to x axis....you will have a fixed hyp.

As the hypotenuse is constant the squares of the adjacent and opposite sides will always be equal.

or a1^2+b2^2=a2^2+b2^2
I guess one could prove it from here on....

a1^2-a2^2=b2^2-b1^2
(a1+a2)(a1-a2)=(b2+b1)(b2-b1).. lost here!
try taking values.... you will get what im trying to suggest!
Ok I understood that part. But how do you know that the point Q is the reflection of the point P? I know those points are on the circle and the radii should be equal. But couldn't the point of Q be on any part of the plain (x and y being +ve)?
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Old 2009 October 18th, 12:08 PM   #16 (permalink)
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IMO (A).
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Old 2009 October 20th, 05:28 AM   #17 (permalink)
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this is gmatprep question OA is A
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Old 2009 October 21st, 03:56 AM   #18 (permalink)
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Quote:
Originally Posted by touche View Post
You are absolutely right!
No calculations needed in this case, where ever point P(X,Y) is, Q will be (y,x)!

How did you come to this conclusion?

Thanks
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Old 2009 November 1st, 10:05 AM   #19 (permalink)
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Originally Posted by morpheus1976 View Post
How did you come to this conclusion?

Thanks
Sorry, wrong conclusion, that would happen in only 3 situations!
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Old 2009 November 4th, 03:14 AM   #20 (permalink)
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IMO-A
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