SachinThorat Posted July 16, 2013 Share Posted July 16, 2013 The average of 5 positive numbers a b c d and e is 16 and a a) 16 b) 18 c) 19 d) 20 e) 22 Quote Link to comment Share on other sites More sharing options...
Masuraha Posted August 14, 2013 Share Posted August 14, 2013 The answer should be 19 that is option c. Median is the middle number, thus the median in this case is C. 16 X 5 = 80. E is 40 thus a+b+c+d= 40. In order for C to have the largest possible value we make C less than d but very close to d, Thus the answer is 19. Quote Link to comment Share on other sites More sharing options...
BGPC Eliza Posted November 20, 2014 Share Posted November 20, 2014 (edited) so we will maximize the median or C, by minimizing the rest of the numbers we'll make a=1 and b=2 (because of the inequality none of them will be the same). We'll make c=x and then d=x+1. We know already that e is 40 The average of the 5 numbers = 16, which means that the sum of all 5 numbers = 80, thus 1+2+x+x+1+40=80 or 2x+44=80 or x=18 Edited November 21, 2014 by BGPC Eliza Quote Link to comment Share on other sites More sharing options...
gschmilinsky Posted March 13, 2015 Share Posted March 13, 2015 There are 5 numbers it says, not 6, so 1+1+x+x+40=5*16 --> 2x = 38 --> x =19 option C. Personally, I would just plug numbers, it's a lot faster. Quote Link to comment Share on other sites More sharing options...
YaSvoboden Posted March 14, 2015 Share Posted March 14, 2015 18. The strict inequalities matter Quote Link to comment Share on other sites More sharing options...
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