liorb1 Posted August 29, 2014 Share Posted August 29, 2014 Hello everyone! I've been struggling quite a lot to crack the following questions, without much success unfortunately... Your help ill be appreciated... 1. The girls' volleyball team is going to have a practice game, by separating the 12 players into 2 teams of 6 players. What is the probability that Vivian and Veronica will be on the same team? 2. A small company had 11 female employees and 13 male employees. If 5 employees are to be selected to work on a project and the CEO insists that there be at least 1 employee of each gender working on the project, how many different project teams can be selected? 3. The girls' volleyball team is going to have a practice game, by separating the 12 players into 2 teams of 6 players each. If Vivian and Veronica can't be on the same team, how many possibilities are there? Thanks a lot! Quote Link to comment Share on other sites More sharing options...
Tristar Posted May 17, 2015 Share Posted May 17, 2015 Hi there! Please find below the solutions to your questions that I came up with: 1. The girls' volleyball team is going to have a practice game, by separating the 12 players into 2 teams of 6 players. What is the probability that Vivian and Veronica will be on the same team? Ans: 6 players can be arranged out of total 12 people in 12C6 ways = 924 (total number of outcomes). If two players are to be on the same team, then the remaining 4 places on a team should be distributed among 10 other players. This can be done in 10C4 ways = 210 (favorable number of cases). So, the probability that Vivian and Veronica will be on the same team is given by: Probability (Vivian & Veronica on the same team) = 210/924 or 0.22. 2. A small company had 11 female employees and 13 male employees. If 5 employees are to be selected to work on a project and the CEO insists that there be at least 1 employee of each gender working on the project, how many different project teams can be selected? Ans: If out of 5 people to be selected to work on a project there is at least 1 employee of each gender, then there will be 3 vacant places in a team to be potentially filled up by the remaining 22 people (10 females and 12 males). The number of different project teams that can be selected is given by: 22C3 ways = 1540. 3. The girls' volleyball team is going to have a practice game, by separating the 12 players into 2 teams of 6 players each. If Vivian and Veronica can't be on the same team, how many possibilities are there? Ans: Probability (Vivian & Veronica NOT on the same team) = 1 - Probability (Vivian & Veronica ON the same team)= =1 - 0.22 = 0.78. Cheers! Quote Link to comment Share on other sites More sharing options...
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