Error in Kaplan CAT 1 DS?

[saitoh7]

If x^2 + 5y = 49, is y an integer?
(1) 1 < x < 4
(2) x^2 is an integer

Answer: E

It's C because if you have both 1 & 2, you get 1 < x < 4 where x is an integer, so x must either be 2 or 3, and so y is an integer. However, the Kaplan explanation says if we choose C, then x can be either 2 or 3 OR 1. Wouldn't x only be 1 if we have 1 <= x <= 4, instead of 1 < x < 4 ??

Is this an error on Kaplan's part?
Thanks

[scoot]

I agree. The ans ahould be C.

[metodiev]

Actually Kaplan is right because from 1) you get that y=(49-x^2)/5 which may or may not be an integer
well, 2 says that x^2 is an integer, but what if x^2 = 3, when x = sqrt(3), 1< sqrt(3) < 4 which also satisfies 1) hence E

[scoot]

I missed this. Agreed with metodiev.

[saitoh7]

ah ok i missed that too. So the Kaplan explanation is wrong ?

[soz_gmat05]

I agree with metodiev as well . Ans should be E

though you can find similar questions in this forum