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#31 (permalink) |
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I Can.
![]() ![]() Join Date: Feb 2008
Posts: 174
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Hi Guys
Here is my take on problem 1.... 1. There is a set of characters, A B C D E F G H I J K. There are 4 character and 3 character codes to be made out of these characters. What is the ratio of the total number possibilities of the 4 character codes to the total possibilities of the 3 character codes? Solution: We are given a set of 11 characters {A,B,C,D,E,F,G,H,I,J,K} 4 character codes AND 3 character codes need to be made out of this set Problem mentions the SET with 11 characters only. Total no of ways to get 4 char code: P(11,4) + P(8,4) Total no of ways to get 3 char code: P(7,3) + P(11,3) (The explanation to get these is below.) Answer is : 8:1 You can either select 4 character code first, hence P(11,4) Now to select 3 char code, we are left with 11-4=7 chars, hence P(7,3) On the other hand if you selected 3 letter code first then P (11,3) To select 4 letter code, we are left with 11-3 = 8 chars, hence P(8,4) |
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