set III

[jatinet]

Q1: [x] denotes the least integer greater or equal x, [2x]=?

1) [x]=1

2) [3x]=1

 

Q2: 1

1) a+b+c+d=170

2) abcd=2^16

[rv_blitz]

Q1 : B.

if [3x]=1, then 0

[Paliwal800]

1. The correct answer is B.

Since [x]=1 might have x=1/4 as well as x=4/5 therefore it is not possible to determine [2x] (whether 1 or 2).

From [3x] =1 it follows that x

 

2. The correct answer is A

From the Q the values can be in the form 2^1, 2^2 .... 2^7 .. 2^9 and so on. Hence possible values a,b,c,d can take are

2,4,8,16,32,64,128,264 so on.

Since a + b +c + d =170 therefore plug the values and you can find that the only possible values can be 2,8,32,128 which satisfy this eq. and from the Q 1

 

From abcd=2^16 , there are two combinations (more than 1 combination)

 

HTH.

 

Cheers,

Neel

[rd_eastbay]

1 -

(1) 0 0

(2) 0 0

B.

 

2.

(1) 2, 8, 32, 128 is the only possible combination. Suff.

(2) Above combination is possible plus, 2, 16, 32, 64 Insuff.

A.