Cost

[scoot]

The cost of sending a package is T cents for the first 1/4 kg and T/20 cents for each additional kg or fraction thereof. What is the cost, in cents, to send a P kilogram package at this rate, where P is an integer greater then 1?

a) PT/20
b) (PT-1)/20
c) [(P/4)+1]/20
d) [(6p-1)20]/20
e) [4(p+1)]/5

[Madhavi_Polisetti]

Cost of the first 1/4 kg = T
Remaining kg = P-1/4 = P-1 (integer) + 3/4 (fraction)
Cost = (P-1) T/20 + (T/20) = PT/20

Total = PT/20 + T

My answer doesn't seem to match any of the above ?

[malice.unlimited]

Let P=4Kg, T=20cents, then T/20=1 cent
So total cost = 20cents*1kg + 1 cent*3kg = 23
replacing values of P &T in the above equations, we'll arrive at (d) as the answer

[scoot]

Official Answer is E for this question. I solved this by picking numbers. It took me around 5 min. I am looking for shortcut for this.

malice,

you equation should be
total cost= 20cents*1/4kg + 1 cent*3*3/4kg

[malice.unlimited]

edited

[he_hels]

Cost of the first 1/4 kg = T
Remaining kg = P-1/4 = P-1 (integer) + 3/4 (fraction)
Cost = (P-1) T/20 + (T/20) = PT/20

Total = PT/20 + T

My answer doesn't seem to match any of the above ?

Agree with Madhavi

[Madhavi_Polisetti]

Cost of 1/4kg = T cents = 20 cents

If the cost of 1/4kg is T cents (or 20 cents) , it is T cents. I wouldn't think that we multpily 1/4 * T.

P-1/4 = 3+3/4
Cost of the remaining kg = Cost of 3kg + 3/4 kg
Cost of additional kg = 3 *T/20 = 3cents (T/20 = 1)
Cost of fraction thereof = T/20 = 1


Total cost = 24cents


Please

[Madhavi_Polisetti]

Assuming, P=4kg T=20 cents

Cost of 1/4kg = T cents = 20 cents

If the cost of 1/4kg is T cents (or 20 cents) , it is T cents. I wouldn't think that we multpily 1/4 * T.

P-1/4 = 3+3/4
Cost of the remaining kg = Cost of 3kg + 3/4 kg
Cost of additional kg = 3 *T/20 = 3cents (T/20 = 1)
Cost of fraction thereof = T/20 = 1


Total cost = 24cents
and none of answers match it.

Please correct me if I'm mistaken.

[Amorous]

I think Madhavi is correct here...

-Amor

[malice.unlimited]

oops..u're right madhavi. a very silly one on my part. sorry..