Ques on MEAN

[wakau]

TRY these OUT !!

1.
If N is 3 times of the mean of 15 numbers,
what is the ration of N to the 16 numbers (including N)?

2.
The average (arithmetic mean) of the 5 positive integers k, m, r, s, and t is 16, and k < m < r < s < t. If t is 40, what is the greatest possible value of the median of the 5 integers?

16

18

19

20

22

Will post the Official Answer later ??

[dsaqwert]

1.
If N is 3 times of the mean of 15 numbers,
what is the ration of N to the 16 numbers (including N)?

i assume this as the ratio of N to the sum of the 16 numbers
N/(5N+N)=1/6

2.
The average (arithmetic mean) of the 5 positive integers k, m, r, s, and t is 16, and k < m < r < s < t. If t is 40, what is the greatest possible value of the median of the 5 integers?

16

18

19

20

22

k+m+r+s+t=80
k+m+r+s=40
1+2+18+19

[karmaholic]

1. N = 3* (sum of 15 numbers, S)/15

The question asks the ration N/(N+S) = (3*S/15)/[S+(3*S/15)]
= (S/5) / [6*(S/5)]
= (S/5) * (5/6S) = 1/6. (The required ratio)

2. Agreed with dsaquert, it works out to be 18.

[Naku]

Why can't we consider one of the number as 0?

[ken_english]

1/6 for me too

[LegoLife]

My answers are :

1) 1/6
2) 18.

Agree with the above explanations.

[nikiforos]

1. 1/6
2. 18

0 cannot be included as 0 is neither positive nor negative