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## geometry questions

Q ) The ratio of the sides of triangle are 2:3:5 and the length of largest side is 52. What is the area of triangle?

Q) The circle lies at the origin of the x- plane with the radius 5. Line K is tangent to circle at [-(2^1/2), (2^1/2)]. find the y-intercept of the line K.

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For question 2, the line is not tangent because the distance from origin to the point (-sqrt(2), sqrt(2)) is not equal to 5 (radius of the circle).

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Originally Posted by yoda_ngen
For question 2, the line is not tangent because the distance from origin to the point (-sqrt(2), sqrt(2)) is not equal to 5 (radius of the circle).
instead of using radius 5, use the radius appropriate to question. I cant recall the exact radius.Just want to know the right approach

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for q 1 sum of 2 sides equals third hence no such tri is possible

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Originally Posted by dv_dheeraj
for q 1 sum of 2 sides equals third hence no such tri is possible
and what would be the solution if we change the ratio to

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Q2. the y -intercept (0, 4*sq.root 2)
Radius = 4, but it doesn't matter here.
y=mx+c, where m- slope, c - y-intercept.
Slope of the tangent line m=1
y-2*sq.root2=1*(x-(-2*sq.root2)
y=x+4*sq.root2
c=4*sq. root 2

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Thank you very much Ankost..

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5x=52 find all three sides of tri find semi perimeter and then the area using semiperimeter formula
A=sqrt(s(s-a)(s-b)(s-c))

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For Q1) can we do like this
Let a, b,c be 3 sides
5x = 52 , find out x , ==> c (big side)
find a, b using 2:4:5 ratio

TO find out area of Triangle we need b & h
To calculate h make this triangle as two 90 degree triangles
using pythgress theorem find out h
then use the formula .5bh

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Q1.
If the ratio of the sides were 3:4:5, a straight approach can be used, as it would be a right triangle. Otherwise, use the semiperimeter formula, but IMHO it takes more than 2 minutes.

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