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Thread: geometry questions

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    geometry questions

    Q ) The ratio of the sides of triangle are 2:3:5 and the length of largest side is 52. What is the area of triangle?

    Q) The circle lies at the origin of the x- plane with the radius 5. Line K is tangent to circle at [-(2^1/2), (2^1/2)]. find the y-intercept of the line K.

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    For question 2, the line is not tangent because the distance from origin to the point (-sqrt(2), sqrt(2)) is not equal to 5 (radius of the circle).

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    Quote Originally Posted by yoda_ngen
    For question 2, the line is not tangent because the distance from origin to the point (-sqrt(2), sqrt(2)) is not equal to 5 (radius of the circle).
    instead of using radius 5, use the radius appropriate to question. I cant recall the exact radius.Just want to know the right approach

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    for q 1 sum of 2 sides equals third hence no such tri is possible

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    Quote Originally Posted by dv_dheeraj
    for q 1 sum of 2 sides equals third hence no such tri is possible
    and what would be the solution if we change the ratio to
    2:4:5. Can u please explain?

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    Q2. the y -intercept (0, 4*sq.root 2)
    Radius = 4, but it doesn't matter here.
    y=mx+c, where m- slope, c - y-intercept.
    Slope of the tangent line m=1
    y-2*sq.root2=1*(x-(-2*sq.root2)
    y=x+4*sq.root2
    c=4*sq. root 2
    Last edited by Ankost; 01-15-2006 at 05:47 PM.

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    Thank you very much Ankost..
    Last edited by kamranalam81; 01-16-2006 at 01:05 AM.

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    5x=52 find all three sides of tri find semi perimeter and then the area using semiperimeter formula
    A=sqrt(s(s-a)(s-b)(s-c))

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    For Q1) can we do like this
    Let a, b,c be 3 sides
    5x = 52 , find out x , ==> c (big side)
    find a, b using 2:4:5 ratio

    TO find out area of Triangle we need b & h
    To calculate h make this triangle as two 90 degree triangles
    using pythgress theorem find out h
    then use the formula .5bh

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    Q1.
    If the ratio of the sides were 3:4:5, a straight approach can be used, as it would be a right triangle. Otherwise, use the semiperimeter formula, but IMHO it takes more than 2 minutes.

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