supurna Posted February 7, 2006 Share Posted February 7, 2006 4) In a certain deck of cards, each card has a +ve integer written on it. In a multiplication game, a child draws a card and multiplies the integer on the cards by the next large integer. If each possible product is between 15 and 200, then the least and the greatest integers on the cards could be 3 &15 3&20 4&13 4&14 5&14Please post the procedure as well. I am clueless.:rolleyes: Quote Link to comment Share on other sites More sharing options...
jyothsnams Posted February 7, 2006 Share Posted February 7, 2006 in such kind of problems substitute the choices in ur equations/comparisions n see which one satisfies.. here the comparision is 15 4 & 13 would satisfy it . Quote Link to comment Share on other sites More sharing options...
yoda_ngen Posted February 8, 2006 Share Posted February 8, 2006 I think it should be D. 4 & 14. My reasoning is that for least number.. for 15 = 3*5 (not possible as they are not consecutive numbers). Next least number would be = 4*5 = 20 For greatest number, you can have 14 *15 = 210 The second greatest number would be = 13 *14 = 182 Since 4 & 15 is not given as a choice. 4 *14 would be the answer. Quote Link to comment Share on other sites More sharing options...
jyothsnams Posted February 8, 2006 Share Posted February 8, 2006 I think it should be D. 4 & 14. My reasoning is that for least number.. for 15 = 3*5 (not possible as they are not consecutive numbers). Next least number would be = 4*5 = 20 For greatest number, you can have 14 *15 = 210 The second greatest number would be = 13 *14 = 182 Since 4 & 15 is not given as a choice. 4 *14 would be the answer. the child multiplies the number on the card n the next consecutive number... so the possible card to satisfy the comparision cud be 13 and not 14...bcoz if it is 14 the child wud multiply 14 with 15 which doesnt comply with the comparision 14*15 (4 n 13) right Quote Link to comment Share on other sites More sharing options...
supurna Posted February 8, 2006 Author Share Posted February 8, 2006 all right!! 4& 13 is indeed the OA Quote Link to comment Share on other sites More sharing options...
kamal_gmat2005 Posted February 10, 2006 Share Posted February 10, 2006 but where in the question has it been stated that the numbers are consecutive. it just said the number is being multiplied by the next large number in the deck of cards. we dont know if they were consecutive do we. Quote Link to comment Share on other sites More sharing options...
sidnim Posted February 10, 2006 Share Posted February 10, 2006 the cards hv a +ve integer on them. The child multiplies that integer by the next large integer...that means if the child drew 4, the next large integer after 4 is 5, hence it is 4*5. i.e. it is in effect consecutive Quote Link to comment Share on other sites More sharing options...
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