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Probability-neither A nor B


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Range = max prob - min prob.

 

P(A or B) >= P(A)

P(A or B) >= P(B)

 

Editing..am still debating how to approach this pblm

0.5

Range of P(A or B) = 0.4

 

I guess, my initial approach was in line with sdasar's explanation below:

 

maximize P(A or B)

P(A or B) = P(A) + P(B) - P(A&B)

for max prob => P(A&B) = 0 ( A and B are mutually exclusive)

=> 0.9

neither = 0.1

 

minimize p(A or B) = p(A) + p(B) - P(A&B)

p(A&B) = p(A)*P(B) for independent events

= 0.5*0.4 = 0.2

p(A or B) = 0.7

neither = 0.3

 

Range = 0.3-0.1 = 0.2

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The other way of doing is

 

When A & b are mutually independent events:

 

The probability that A won't happen is 0.5

The probability that B won't happen is 0.6

 

Probability that both events (neither A nor B) happen is 0.3

 

When A & B are mutually dependent(exclusive) events:

 

The probbality that either A or either B happen is 0.9 and none of them happen is 0.1

 

The range is 0.2

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GMAT-HELP,

 

0.3 and 0.1 refers to well defined populations. One probablity refers to truly independent random events and the other to truly mutually exclusive events.

 

If there is any bias between events A and B as you eluded, all bets are off. I don't think the problem (based on the answers) is implying anything other than the above scenarios.

 

Thanks,

sdasar

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The other way of doing is

 

When A & b are mutually independent events:

 

The probability that A won't happen is 0.5

The probability that B won't happen is 0.6

 

Probability that both events (neither A nor B) happen is 0.3

 

When A & B are mutually dependent(exclusive) events:

 

The probbality that either A or either B happen is 0.9 and none of them happen is 0.1

 

The range is 0.2

 

Sdasar: how do you get P(both events won't happen) = 0.3?

 

Gmathelp: like your 2nd explanation. thanks

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