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Old 09-21-2006, 09:40 PM   #1 (permalink)
tamannaw
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probability

Please explain the answers to the following question:

1.What is the probability that events A and B both occur?
(1) The probability that event A occurs is 0.8.
(2) The probability that event B occurs is 0.6.
Thanks!
2.
. In the xy-plane, does the point (4, 12) lie on line k ?
(1) The point (1, 7) lies on line k.
(2) The point (-2, 2) lies on line k
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Old 09-21-2006, 10:53 PM   #2 (permalink)
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1st Q...
Probability of events A&B to occur = Probability of A*Probability of B
so A&B= 0.8*0.6=.53
The answer is (C)

2nd Q...
Y=Mx+b
Slope (M)= (7-2)/(1+2)=>5/3
7=(5/3*1)+b=> b=16/3
so=> 12=(5/3*4)+16/3
=>(20/3+16/3)
=36/3=12
The answer is (C)
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Old 09-21-2006, 11:21 PM   #3 (permalink)
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thanks!
however ans for q 1 is e
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Old 09-21-2006, 11:27 PM   #4 (permalink)
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Hmm.. then it might be becuase we do not know if the two events are independent or mutually exclusive?!?!!!!
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Old 09-22-2006, 05:59 AM   #5 (permalink)
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Gunit you are right we dont know the relation betw events
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Old 09-22-2006, 01:49 PM   #6 (permalink)
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1.What is the probability that events A and B both occur?

P(both A&B)=P(A)*P(B) if two events are dependent
P(both A&B)=P(A)+P(B) id two events are independent

(1) The probability that event A occurs is 0.8.
no info about event B (0, 1.0) - not sufficient

(2) The probability that event B occurs is 0.6.
no info about event A(0,1.0) - not sufficient

(1)+(2) P(A)=0.8 and P(B)=0.6

no info if P(A) and P(B) are dependent or independent
not sufficient

answer= E

2.
In the xy-plane, does the point (4, 12) lie on line k ?

y=mx+c

(1) The point (1, 7) lies on line k.
7=m+c
=not sufficient
(2) The point (-2, 2) lies on line k
2=-2m+c
not sufficient

(1)+(2)
7=m+c and 2=-2m+c => 7-2=m+2m=>m=5/3 AND c=7-5/3=16/3
y=mx+c = (5/3)x+(16/3) = (5x+16)/3
if (4,12) lies on line k then it must satisfy above equation
y=12, mx+c=(5*4+16)/3=36/3=12 which is TRUE

sufficient

answer = C

BTW for DS Qs we don't need to see if it really lies on line K or not...all we need to make sure there is enough info to find that out.

Last edited by skarya : 09-22-2006 at 02:06 PM.
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Old 09-22-2006, 04:27 PM   #7 (permalink)
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Thanks everybody!
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Old 09-06-2008, 08:29 AM   #8 (permalink)
nh8404052006
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please check out this link:
http://www.urch.com/forums/gmat-data...-one-more.html (One more.)
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