It is D = 15
2^x - 2^(x -2) = 3 (2^13)
(3 * 2^x)/4 = 3 (2^13)
3 * 2^x = 3(2^15)
Hence x = 15
Elton
Hi,
I received the following question on the practice test, so I know the right answer, I just can't figure out the process of getting the answer. Could someone please explain step by step the method for solving this? I tried a post on ScoreTop, but I was unable to even understand the explanation. This one is driving me crazy, I must be missing something!!! Thank you!
Question:
If 2^x - 2^(x-2) = 3(2^13), what is the value of x?
a) 9
b) 11
c) 13
d) 15
e) 17
Thanks again for the assistance!

2^(x-2) can be rewritten as 2^x/2^2 or 2^x/4
So now on the left side we have:
2^x - 2^x/4
To get a common denominator multiply the first term by 4/4
(4*2^x - 2^x)/4
This is where the 3 comes from: factor out 2^x
[2^x * (4 - 1)] / 4
(2^x * 3) / 4
Now we can finish
2^x * 3 = 4 * 3 * 2^13
2^x * 3 = 2^2 * 2^13 * 3
2^x * 3 = 2^15 * 3
x = 15




There are currently 1 users browsing this thread. (0 members and 1 guests)
Bookmarks