Perimeter

[o_0]

The perimeter of a right angle isosceles triangle is 16 + 16(sqrt(2)). What's the hypotenuse?

[scorpion.ks]

Let equal side = a and hypotenuse = h

h^2 = a^2 + a^2
=> a = h/sqrt(2)

Also, 2a + h = 16 + 16(sqrt(2))
putting, a = h/sqrt(2), in this eq, we get,

h + h(sqrt(2)) = 16 + 16(sqrt(2))
=> h = 16

[DMoney]

h + h(sqrt(2)) = 16 + 16(sqrt(2))
=> h = 16

Not sure how you got H+H(rt2)... i keep getting Hrt2+2H/rt2...