1. Good post? |
There are 5 married couples and a group of three is to be formed out of them; how many arrangements are there if a husband and wife may not be in the same group?

2. Good post? |
Hi Testmagicians,

Am not sure, so correct me if I'm wrong.

There are 10 people, 5 husbands and 5 wives. 3 people can be chosen as 2 Husbands and 1 wife or 2 wives and 1 husband. This can be done in 5C2*3C1 (excluding those two husbands wives) + 5C2*3C1

Hope this helps

Shivani

3. Good post? |
Hi Testmagicians,

I would like to add to the above post 3 people can also be chosen as 3 husbands or 3 wives (3C1 + 3C1) = 6 additional ways

Shivani

4. Good post? |
Hi,

In my opinion, the question can be solved in the following manner:
Husband and wife not in same group = Total no. of arrangements - (Husband and Wife together)

Since there are 10 people --> Total = 10C3 = 120

Husband and Wife together in group = (Choose 1 couple out of 5 accounting for 2 earthlings in the group) x (Choose one person out of the remaining 8 people)
-->5C1 x 8C1 = 40

Ans= 120 - 40 = 80

5. Good post? |
what is the correct ans

6. Good post? |
Is the question says that a group of 3 couples needs to be formed or a group of 3 people?

Question seems a little vague to be an official type question

7. Good post? |
I think the question is asking for 3 people to form a group. So how many 3 person groups can be arranged so that no married couple is within the same 3 person group.

8. Good post? |
Excellent Daffyduck...you have nailed it...the answer is 80

Metal.

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