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Old 07-24-2008, 01:23 AM   #1 (permalink)
Atonio79
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Function Question

For which of the following functions is f(a+b)= f(a)+f(b) for all positive numbers a and b?

a. f(x)=x^2
b. f(x)= x+1
c. f(x)= x^(1/2)
d. f(x)= 2/x
e. f(x)= -3x
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Old 07-24-2008, 02:24 AM   #2 (permalink)
Retake_GMAT
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f(x) = x^2

f(a + b) = (a+b)^2 which is not equal to a^2 + b^2 i.e. f(a) + f(b)


f(x) = x + 1

f(a + b) = a+b+1 which is not equal to a+1 + b+1 i.e. f(a) + f(b)


f(x) = sqrt x

f(a + b) = sqrt(a+b) which is not equal to sqrt(a) + sqrt(b) i.e. f(a) + f(b)


f(x) = 2/x

f(a + b) = 2/(a+b) which is not equal to 2/a + 2/b i.e. f(a) + f(b)


f(x) = -3 x

f(a + b) = -3(a+b) = -3a -3b = f(a) + f(b)

ans E
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Old 07-24-2008, 04:32 AM   #3 (permalink)
Anson800
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Imo E
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Old 07-24-2008, 05:32 AM   #4 (permalink)
GmatG
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Quote:
Originally Posted by Retake_GMAT View Post
f(x) = x^2

f(a + b) = (a+b)^2 which is not equal to a^2 + b^2 i.e. f(a) + f(b)


f(x) = x + 1

f(a + b) = a+b+1 which is not equal to a+1 + b+1 i.e. f(a) + f(b)


f(x) = sqrt x

f(a + b) = sqrt(a+b) which is not equal to sqrt(a) + sqrt(b) i.e. f(a) + f(b)


f(x) = 2/x

f(a + b) = 2/(a+b) which is not equal to 2/a + 2/b i.e. f(a) + f(b)


f(x) = -3 x

f(a + b) = -3(a+b) = -3a -3b = f(a) + f(b)

ans E
IMO E. Same as above.
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Old 07-24-2008, 06:23 AM   #5 (permalink)
NishantG
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E for me too

f(a+b) = f(a) + f(b)

if f(a) = -3a

f(a+b) = -3(a+b) = -3a -3b = f(a) + f(b)
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Old 07-24-2008, 03:57 PM   #6 (permalink)
Atonio79
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The Correct Answer is E... Thanks for explanation!
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