Cord

[gcvbt7t]

[FONT='Verdana','sans-serif'][FONT='Verdana','sans-serif']139. Does line L intersect with the curve represented with the equation y=x^2?
(1) L passes through point (2, 5)
(2) L passes through point (2,-5)[/font]
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[chan_space]

I think the answer choice will be "C"

To determine the equ. of line you need at least 2 points. Hence statement 1 and 2 are both in sufficient.

HOwever when taken together, it is sufficient.

[chan_space]

gcvbt7t ... do you know the official answer

[gcvbt7t]

the answer is A

[manikdhingra]

answer shud be e......the line L turns out to be paraleel to y axis.......and i think the equation y=x^2 is a parabola with focus at (0,0)... and facing upwards....so v cant know whether the line intersects it or not

[manikdhingra]

sorry guys i gave the defination of parabola wrong...but by knowing the corect figyre for the parabola y=x^2 we can solve this

[bhuvanprabha]

Imo A

[hawk007]

y= x^2

Y is positive always when ever the x value is taken

IMO A

where as in 2 y is negative can it be possible if y=x^2 y always has to be positive so we cannot determine throught 2nd point i guess
so

so answer is A

[ankitharish]

IMO c.

Explaination.

1)L passes through 2,5

y = x^2 is an upward facing parabola passing through the point 0,0

Since 5 is not eq to 2^2.We know at least that this point does not lie on the parabola.Another point on the line may or ,may not lie on the parabola.

2)L passes through 2,-5.
This point surely does not lie on the parabola ,since this is on the 4th quadrant ehile the parabola will encompass the 1st and the 2nd quadrant.

Combining both :

Imagine a line or draw one from point 2,5 to 2,-5.

It will be a straight line paralel to y axis passing through points
(2,4) (2,3) (2,2)........ 2,-5.

See this line passes through 2,4 and our equation of the parabola is y = x^2.
for x=2,y=2^2=4.
hence c.

[jaspreetp]

agree with ankitharish