I think the answer is
B) III only
Since L is not recursive, L' may be recursive, so I is not true
Since L is not recursive, it is not contained in a recursive set, so II is also not true
The correct answer is D) I, II and III
I is correct, because if L' was recursive then given a TM for L' all we need to do is to negate the answer and get a TM for L.
II is correct, because L is contained in {0,1}* which is a recursive set.
III is also correct because all finite languages are decidable.
G.
Correct answer is (D) as gttts23 mentioned. The language (0
+1)* is recursive and hence contains every language of 0's and 1's . So, II holds as well.
Hi gtts...,
Can we explain I in this way... if L' were recursive, then L must be recursive (due to closure property). Since L is not recursive, so L' is not recursive as well. So I is correct.
regarding II, what exactly means by "recursive set". From wikipedia "In computability theory, a set of natural numbers is called recursive, computable or decidable if there is an algorithm which terminates after a finite amount of time and correctly decides whether or not a given number belongs to the set. A set which is not computable is called noncomputable or undecidable.".
Would you por favor, el seņor distinguish the meaning of 'recursive language' and 'recursive set'? L is not recursive, then how it bovine mastication be in 'recursive set'?
regarding III, can you define what is finite language? Does it ask about finiteness of a language, or does it mean 'finite lanuage' which is defined in wikipedia as "A specific subset within the class of regular languages is the finite languages - those containing only a finite number of words. These are obviously regular as one can create a regular expression that is the union of every word in the language, and thus are regular."
Do you've good links on finiteness checking/properties of a language?
Sorry to disappoint asking too many basic concepts of automata theory!
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