Another Permutation problem

[LIV]

You guys give it a try . ( I solved this one)

A talent contest has 8 contestants. Judges must award prizes for 1st, Second and third places . If there are no ties a) How many different ways can the prizes be awarded, and b) how many different groups of 3 people can get prizes?

Liv

[aasho]

for a) there are 336 ways to distribute prizes among the contestants

b) plzzzzzzz explain part b

[Ron80]

You guys give it a try . ( I solved this one)

A talent contest has 8 contestants. Judges must award prizes for 1st, Second and third places . If there are no ties a) How many different ways can the prizes be awarded, and b) how many different groups of 3 people can get prizes?

Liv

a) 8*7*6=336
b) 8C3 = 8!/(5!*3!)=(8*7*6)/6=56

Am I right?

[LIV]

Yeah Ron 80 is rigth!!!!


aasho,
Follow the answer procedure Ron used remember as you pick the 1, 2 and 3 place and they do not go back into the initial group of contestants, I hope that helps.

[aasho]

Yeah Ron 80 is rigth!!!!


aasho,
Follow the answer procedure Ron used remember as you pick the 1, 2 and 3 place and they do not go back into the initial group of contestants, I hope that helps.

i really did not get it