i think in question 'abc' means the product of three numbers a,b,c.
If each of the non-zero numbers a,b,c is divisble by 3 ,then abc must be divisbile by which of the following numbers?
B 27 ---answer
Reasoning: if each number-a,b,c is divisble by 3,then
say a= 3 x p ,b=3 x q, c=3 x r
abc = 3x3x3x(pqr) divisible by 27.
Say number is 333 -(not divisible by 27 but each digit divisbile by 3)
I dont understand if in question 'abc' meant to be 'a x b x c' or 'abc'.
Yes,This is a small error in thw ques ans answer as well in Nova GRE book.I hope not to see such ambiguities on the real exam.
For abc -anyone would be clearly considering it as number formed by digits -abc ...
With that ,the reasoning given doest fit well.
If 'abc' ='a x b x c' ,then it fits but Q should have written a.b.c atleast to represent product.
I have seen many such small errorsi n Novas book (specially in answers-explanation ) which dumbfounds me and wastes so much of my time to come out of confusion.
abc here refers to a*b*c and I don't think there is any problem with the question.
we can write the equation as follows :
a/3 = 0------------1.
b/3 = 0------------2.
c/3 = 0------------3.
Now if we multiply the three equations (number 1 * number 2 * number 3) we get
a/3*b/3*c/3 = 0*0*0
or we can write it as : abc/27 = 0
Hence answer will be 27.
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