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#1 (permalink) |
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I JUST got here.
Join Date: Sep 2009
Posts: 15
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drraju's problem please solve it
1. Given (1/(x+y)) 1 + (1/(x-y)) 1 = 4. Which of the following must be true?
I. x = 2 II. y = 0 III. y = -1 A. Only I B. Only II C. Both I and III & so on 2. .Given a train p travelling a distance s km at an average speed of r km/hr and another train t travels a distance y at a speed of z km/hr. Find the equation which satisfies the above problem? A.sr - yz > 0 B. sz - yr > 0 C. yz sr > 0 D. ry.sz > 0 E. sy rz > 0 (Something similar to this) |
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#2 (permalink) |
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Within my grasp!
![]() ![]() Join Date: Feb 2009
Posts: 135
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To number 1 :
ive got to th point that i would choose so on... because iam stock at this equation and nothin has to be in my opinion.... -2y= 6(x^2-y^2) i`ll think this excercise makes no sense.... to number 2 ... to munim M ive read it, tried to solve it but didnt come to an solution because ive thought s.th. is missing so i looked after it at dr.raju and u missed one important information to tell ....so this is the complete question Given a train ‘p’ travelling a distance ‘s’ km at an average speed of x km/hr and another train ‘t’ travels a distance ‘y’ at a speed of z km/hr. If the time taken by train ‘p’ is less than train ‘t’, then find the equation which satisfies the above problem? For p: T=D/R Time =Distance/Rate so...T=S/X For T T=y/z and u have the info that p takes less time then t (train) so s/x < y/z s*z < y*x sz-yx <0 so look at the answer choices and we `ve only a.-choices which are greater than 0 sz-yx<0 times (-1) yx-sz>0 hence d .... hope its simple to understand!!! |
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