Arithmetic mean

[rupali41]

If the average (arithmetic mean) of x, y, z, 5, and 7 is 8,
which of the value for x = 1?
I The median of the five numbers cannot be 5
II At least one of x, y and z is greater than 9
III The range of the five numbers is 2 or more
(A) I only
(B) II only
(C) III only
(D) I and III
(E) II and III

Can anyone help?

SPOILER: OA: E

[Curly213]

okay , i`ll think i have the solution ...
first x+y+z+5+7=8*5=40
so x+y+z = 28
our condition was that x=1
so x+y = 27
so these two variables could be positive...or one is positive and the other is negative...
1. why not lets say our five numbers would be -7 ,1,5,7, 34
in this case 5 would be our median .. so it is possible ... so 1 aint true

2. like i said y and z could be both possible or one positive and one negative
case a) both positive then for example 12+15 =27
or 10 + 17, or 5+22
as u can seein every case one number is greater than 9
case b ) if one is negative then the other has to be bigger than 9 to add up to 27!!!
so 2 is true!!!

3)
for the last get agree with the statement that range is more than 2 but ...i dont kno a way where it should be 2 ... thats all i can say so far ..
hope it helped