verdant Posted September 26, 2004 Share Posted September 26, 2004 n is not 0 n/12 (n+4)/3 Quote Link to comment Share on other sites More sharing options...
Azzkikr6969 Posted September 26, 2004 Share Posted September 26, 2004 n/12 n+4/3. I would say there's not enough information to determine this problem. Quote Link to comment Share on other sites More sharing options...
rashmi Posted September 26, 2004 Share Posted September 26, 2004 answer is D. try putting some workable values of n.most easy ones are 12,-12 Quote Link to comment Share on other sites More sharing options...
simba Posted December 17, 2005 Share Posted December 17, 2005 answer is D. try putting some workable values of n.most easy ones are 12,-12 now where r the options here??:( Quote Link to comment Share on other sites More sharing options...
kronique Posted December 17, 2005 Share Posted December 17, 2005 now where r the options here?:( In a comparison prob. the options are usually std. eg. A) Col.A is greater B) Col. B is greater C) Both are equal D) Not enough info. available to solve the prob. by the way i would say ans. is D for this case. Quote Link to comment Share on other sites More sharing options...
Astra81 Posted December 17, 2005 Share Posted December 17, 2005 I subtracted the second from the first (-3n/12-4/3) and plugged in numbers. letting n=100 gives a negative result, so the first is smaller. whereas lettingn it =-100 gives a +ve result, which indicates that the first is larger, thus D Quote Link to comment Share on other sites More sharing options...
simba Posted December 17, 2005 Share Posted December 17, 2005 In a comparison prob. the options are usually std. eg. A) Col.A is greater B) Col. B is greater C) Both are equal D) Not enough info. available to solve the prob. by the way i would say ans. is D for this case. In that case it would be D, I worked on it and found it wld have been A if n-16/3 or C if n=16/3 As nothing is mentioned, it wld b D. Quote Link to comment Share on other sites More sharing options...
askrach Posted December 22, 2005 Share Posted December 22, 2005 hi everybody,could anybody explain me how to slove this question, A retail business has determined that its net income,in terms of x,the number of items sold,is given by the expression x^2+x-380. Colm A=the number of items that must be sold for the net income to be zero. colm B= 10. Quote Link to comment Share on other sites More sharing options...
kronique Posted December 22, 2005 Share Posted December 22, 2005 hi everybody,could anybody explain me how to slove this question, A retail business has determined that its net income,in terms of x,the number of items sold,is given by the expression x^2+x-380. Colm A=the number of items that must be sold for the net income to be zero. colm B= 10. hi rach. I think the Q means when the no. of items sold = x^2 + x - 380, net income is "x". so for net income to be 0, no. of items to be sold = 0, instead the firm should buy 380 items . ( by substituting x=0 in the no. of items sold eqn. ) hence Col A = 0 hence i would say Col. B is greater. is this correct ? Quote Link to comment Share on other sites More sharing options...
Astra81 Posted December 22, 2005 Share Posted December 22, 2005 net income = x^2+x-380 where x is the number of items sold The number of items that must be sold (i.e. x) for the net income to be zero. x^2+x-380 = 0 --> x = 19 19 > 10 --> Answer is A Quote Link to comment Share on other sites More sharing options...
mauveÄster Posted December 22, 2005 Share Posted December 22, 2005 hi everybody,could anybody explain me how to slove this question, A retail business has determined that its net income,in terms of x,the number of items sold,is given by the expression x^2+x-380. Colm A=the number of items that must be sold for the net income to be zero. colm B= 10. x here is the number of items sold. Therefore, x^2+x-380=0 Solve this and you will get x=19. So the answer is A Quote Link to comment Share on other sites More sharing options...
kronique Posted December 22, 2005 Share Posted December 22, 2005 x here is the number of items sold. Therefore, x^2+x-380=0 Solve this and you will get x=19. So the answer is A good one mauve & astra...damn me...totally misunderstood the Q .:mad: :mad: Quote Link to comment Share on other sites More sharing options...
mauveÄster Posted December 22, 2005 Share Posted December 22, 2005 good one mauve & astra...damn me...totally misunderstood the Q .:mad: :mad: Dont beat yourself up for this one.. The language was a bit ambiguous:) Quote Link to comment Share on other sites More sharing options...
askrach Posted December 22, 2005 Share Posted December 22, 2005 the is not correct, it a col A is greater. hi rach. I think the Q means when the no. of items sold = x^2 + x - 380, net income is "x". so for net income to be 0, no. of items to be sold = 0, instead the firm should buy 380 items . ( by substituting x=0 in the no. of items sold eqn. ) hence Col A = 0 hence i would say Col. B is greater. is this correct ? yeah ur answer is correct ,but how did u slove the equation. x here is the number of items sold. Therefore, x^2+x-380=0 Solve this and you will get x=19. So the answer is A Quote Link to comment Share on other sites More sharing options...
simba Posted December 24, 2005 Share Posted December 24, 2005 the is not correct, it a col A is greater. yeah ur answer is correct ,but how did u slove the equation. by mean how to solve x^2+x-380=0? thts simple, either go hit n trail also therez a formula like for ax^2 + bx + c = 0 Roots are {-b+sqroot(b^2 - 4ac)}/2a & {-b-sqroot(b^2 - 4ac)}/2a. simba Quote Link to comment Share on other sites More sharing options...
rpgre2005 Posted December 29, 2005 Share Posted December 29, 2005 n is not 0 n/12 (n+4)/3 ans :B is it correct? Quote Link to comment Share on other sites More sharing options...
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