# Thread: GRE Tough Quant Question - Any help would be appreciated!!!!

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## GRE Tough Quant Question - Any help would be appreciated!!!!

For all numbers K, k* = 1/k

Quantity A
((K + 2)*)*

Quantity B
(1/K+2)*

The correct Answer is C. I'm confused as to what the question is saying. I tried to solve it by plugging in 2 for K.
For all numbers 2, 2* = 1/2

Quantity A:
((2+2)*)* = ((4)*)* = 4 * 1/2 = 2 * 1/2 = 1 Can someone please advise me with what I'm doing wrong.

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## Re: GRE Tough Quant Question - Any help would be appreciated!!!!

Hi grehelpme,

GRE loves to ask these types of questions and the good news is these are very difficult to solve.

For this problem, k* = 1/k.

so, (K+2)* = 1/(K+2)
.
=> ((K+2)*)* = (1/(K+2))* which is same as quantity B.

If you want to solve it using an example, Let's say K=2, then

Quantity A: ((2+2)*)* = ((4)*)* = (1/4)* = 4
Quantity B: (1/2+2)* = (1/4)* = 4

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## Re: GRE Tough Quant Question - Any help would be appreciated!!!!

Originally Posted by grehelpme

For all numbers K, k* = 1/k

Quantity A
((K + 2)*)*

Quantity B
(1/K+2)*

The correct Answer is C. I'm confused as to what the question is saying. I tried to solve it by plugging in 2 for K.
For all numbers 2, 2* = 1/2

Quantity A:
((2+2)*)* = ((4)*)* = 4 * 1/2 = 2 * 1/2 = 1 Can someone please advise me with what I'm doing wrong.

The question is very simple...any number k* will be equal to its reciprocal. Just plug in various values for k. First try 2, then 0, then a negative number.... The answer will be C in every case... Thank u

4. Good post? |

## Re: GRE Tough Quant Question - Any help would be appreciated!!!!

Yeah, I think the key to this question is rewriting Quantity A, because ((k+2)*)* = (1/(k+2))*. That way, you can see that the two quantities are equal.