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Thread: GRE Tough Quant Question - Any help would be appreciated!!!!

  1. #1
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    GRE Tough Quant Question - Any help would be appreciated!!!!

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    Hi, Can someone please help me solve this using numbers.

    For all numbers K, k* = 1/k

    Quantity A
    ((K + 2)*)*

    Quantity B
    (1/K+2)*



    The correct Answer is C. I'm confused as to what the question is saying. I tried to solve it by plugging in 2 for K.
    For all numbers 2, 2* = 1/2

    Quantity A:
    ((2+2)*)* = ((4)*)* = 4 * 1/2 = 2 * 1/2 = 1 Can someone please advise me with what I'm doing wrong.
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    Re: GRE Tough Quant Question - Any help would be appreciated!!!!

    Hi grehelpme,

    GRE loves to ask these types of questions and the good news is these are very difficult to solve.

    For this problem, k* = 1/k.

    so, (K+2)* = 1/(K+2)
    .
    => ((K+2)*)* = (1/(K+2))* which is same as quantity B.

    If you want to solve it using an example, Let's say K=2, then

    Quantity A: ((2+2)*)* = ((4)*)* = (1/4)* = 4
    Quantity B: (1/2+2)* = (1/4)* = 4

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    Re: GRE Tough Quant Question - Any help would be appreciated!!!!

    Quote Originally Posted by grehelpme View Post
    Hi, Can someone please help me solve this using numbers.

    For all numbers K, k* = 1/k

    Quantity A
    ((K + 2)*)*

    Quantity B
    (1/K+2)*



    The correct Answer is C. I'm confused as to what the question is saying. I tried to solve it by plugging in 2 for K.
    For all numbers 2, 2* = 1/2

    Quantity A:
    ((2+2)*)* = ((4)*)* = 4 * 1/2 = 2 * 1/2 = 1 Can someone please advise me with what I'm doing wrong.



    The question is very simple...any number k* will be equal to its reciprocal. Just plug in various values for k. First try 2, then 0, then a negative number.... The answer will be C in every case... Thank u

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