Big Dog 04 Posted February 25, 2005 Share Posted February 25, 2005 Q, How do you calculate it? See attachment for question. Thanks.sdp.doc Quote Link to comment Share on other sites More sharing options...
hello_mona Posted February 25, 2005 Share Posted February 25, 2005 hi bigdog, first consider the point where the rt. triangle is formed as E. Since its a parallelogram BC=AD=12. draw a straight line from point C to AD and name it as F. so, DF=CE=2 and CF=ED=4 so now u have AF=10, CF=4 use pythogaraeus theorem on triangle AFC .. u get AC as sqrt(116) = 2sqrt(29) Quote Link to comment Share on other sites More sharing options...
coolpaggy Posted February 25, 2005 Share Posted February 25, 2005 hi big dog 4 !! here is the solution for the Q u asked. its quite simple all u need to do is to drop an extra perpandicular...see, I've put it up in the following attachment... :tup: parallogram_solution.doc Quote Link to comment Share on other sites More sharing options...
Big Dog 04 Posted February 26, 2005 Author Share Posted February 26, 2005 @Thank you very much both of u - you are right it is an easy question once you insert the perpendicular!! Much appreciated. BD Quote Link to comment Share on other sites More sharing options...
Commentor Posted February 26, 2005 Share Posted February 26, 2005 You can avoid that extra perpendicular, if you remember that |AB|^2 + |BC|^2 + |CD|^2 +|DA|^2 = |AC|^2 + |BD|^2 for a parallelogram ABCD. Quote Link to comment Share on other sites More sharing options...
manasi4gre Posted February 27, 2005 Share Posted February 27, 2005 commentor,but i got 2sqrt(41) using AB^2 + BC^2 + CD^2 + DA^2=AC^2 + BD^2....it doesnt match with the ans. drawn by dropping the perpendicular i.e. 2sqrt(29) Quote Link to comment Share on other sites More sharing options...
coolpaggy Posted February 27, 2005 Share Posted February 27, 2005 commentor,but i got 2sqrt(41) using AB^2 + BC^2 + CD^2 + DA^2=AC^2 + BD^2....it doesnt match with the ans. drawn by dropping the perpendicular i.e. 2sqrt(29) Mansi please open the attachment I have uploaded. It'll clear all your doubts. (ale ka laxat ata tari ?) :grad: Quote Link to comment Share on other sites More sharing options...
hello_mona Posted February 27, 2005 Share Posted February 27, 2005 yea commentor..can u pls clarify tht?? coz even i am not getting 2sqrt(29) by using tht method. Quote Link to comment Share on other sites More sharing options...
manasi4gre Posted February 27, 2005 Share Posted February 27, 2005 Mansi please open the attachment I have uploaded. It'll clear all your doubts. (ale ka laxat ata tari ?) :grad: parag, I solved this problem by dropping an extra perpendicular to get the ans. as 2sqrt(29) exactly like the way you did. But i dont seem to get the same ans. applying AB^2 + BC^2 + CD^2 + DA^2=AC^2 + BD^2....the ans. is 2sqrt(41). can you clarify the reason for the two different answers ,commentor? p.s: parag,what do you mean by "ale ka laxat ata tari ?" Quote Link to comment Share on other sites More sharing options...
coolpaggy Posted February 27, 2005 Share Posted February 27, 2005 parag, I solved this problem by dropping an extra perpendicular to get the ans. as 2sqrt(29) exactly like the way you did. But i dont seem to get the same ans. applying AB^2 + BC^2 + CD^2 + DA^2=AC^2 + BD^2....the ans. is 2sqrt(41). can you clarify the reason for the two different answers ,commentor? p.s: parag,what do you mean by "ale ka laxat ata tari ?" I request you to open the attachment I have uploaded in my solution. Please refer to it so no doubts could persist. PS : "ale ka laxat" means, did you undertand now ??? Quote Link to comment Share on other sites More sharing options...
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