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## probability

In how many ways can 11 # signs and 8* signs be arranded in a row so that no two * signs come together?

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wrong solution...

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Vote 12C8 = 495

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Originally Posted by arjmen
Vote 12C8 = 495
I agree with Arj. You've solved this before in the personal statement forum havent you?

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Ish, Can you explain the answer ? :-)

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Originally Posted by ish
I agree with Arj. You've solved this before in the personal statement forum havent you?
Yep.

Here:
http://www.urch.com/forums/showthread.php?t=29195 (* and # - number of ways)

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Thanks arjmen. You have saved Ish's time . LOL . Thanks again

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Originally Posted by manwiththemission2005
You have saved Ish's time .
...

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ok..earthlings..
me still got a doubt
shouldnt it be 12P8
theres afterall, difference betwen the 1st* and the 2nd*...rite?
confused..help

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* of the same type
# of the same type. They didnt specify it as different too

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