serena_greene Posted November 13, 2005 Share Posted November 13, 2005 An artist is invited to exhibit 4 new paintings and 3 new scupltures at a gallery space. If the artist has 7 paintings and 5 sculptures from which he must pick the 7 artworks he will exhibit, how many different possible combinations of paintings and sculptures does he have from which to choose? The answer is supposed to be 350, but I would like to know why. Thanks Quote Link to comment Share on other sites More sharing options...
stickler_nishat Posted November 13, 2005 Share Posted November 13, 2005 7c4*5c3 = 350 we have to choose 4 paintings from 7 paintings........its 7c4. 3 scupltures from 5 scupltures........its 5c3 so, 7c4*5c3=350 Quote Link to comment Share on other sites More sharing options...
priyankagre2005 Posted November 13, 2005 Share Posted November 13, 2005 agree. Quote Link to comment Share on other sites More sharing options...
serena_greene Posted November 13, 2005 Author Share Posted November 13, 2005 Thanks, The explaination they had wasn't very clear. Quote Link to comment Share on other sites More sharing options...
rehoot Posted November 17, 2005 Share Posted November 17, 2005 The notation "7c4" means to calculate all the combinations of groups of 4 taken from a set of 7. This is 7!/(4! * (7-4)!) You can read about it here (search for 10_c_4) http://mathforum.org/dr.math/faq/faq.comb.perm.html Quote Link to comment Share on other sites More sharing options...
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